Hcf of 625 3125 15625
WebDec 31, 2014 · Note that the cycle of the last four digits contains 625, 3125, 5625, 8125, which are 1, 5, 9, 13 times 5 4. Similarly the cycle of the last five digits contains 3125 = 1 × 5 5 53125 = 17 × 5 5 15625 = 5 × 5 5 65625 = 21 × 5 5 28125 = 9 × 5 5 78125 = 25 × 5 5 40625 = 13 × 5 5 90625 = 29 × 5 5 WebJan 24, 2024 · Step (1) : HCF of 625 and 3125 by using Uuclid's division algorithm is 3125=625×5+0⇒H CF of 625 and 3125 is 625. Step (2) : Now HCF of 625 and 15625 will 15625=625×25+0 ⇒ HCF of 625 and 15625 is 625 . Hence HCF of 625, 3125 and 15625 is 625. nce required number is 625 . View solution
Hcf of 625 3125 15625
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WebSince remainder is zero, therefore, HCF (1250, 9375 and 15625) = 625 Hence, 625 is the largest number which divides 1251, 9377 and 15628 leaving remainder 1, 2 and 3, respectively. Concept: Euclid’s Division Lemma Is there an error in this question or solution? 2024-2024 (March) All India (Set 2) Q 19.2 Q 19.1 Q 20 APPEARS IN WebClearly the required number is the HCF of the following numbers 626 - 1 = 625, 3127 - 2 = 3125 and 15628 - 3 = 15625 Case I. Finding the HCF of 625 and 3125 by applying Euclid’s division lemma. I. 3125 = 625 × 5 + 0 Since, the remainder at this stage is zero, so the divisor i.e., 625 at this stage is the HCF of 625 and 3125. Case II.
WebThis means 626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 are completely divisible by the number ∴ The required number = HCF of 625, 3125 and 15625 First consider 625 and 3125 By applying Euclid’s division lemma 3125 = 625 × 5 + 0 HCF of 625 and 3125 = 625 Now consider 625 and 15625 By applying Euclid’s division lemma 15625 = 625 × 25 … WebHCF Calculator: Finding the Highest Common Factor is similar to the Greatest common factor or divisor as HCF is also known as GCF or GCD. You can calculate HCF of given numbers easily by approaching the …
WebNow let us learn how to calculate the prime factors of 3125. The first step is to divide the number 3125 with the smallest prime factor, here it is 5. We keep dividing until it gives a non-zero remainder. 3125 ÷ 5 = 625 625 ÷ 5 = 125 125 ÷ 5 = 25 25 ÷ 5 = 5 5 ÷ 5 = 1 Further dividing 1 by 5 gives a non-zero remainder. WebMar 12, 2024 · We can use this to figure out the HCF of 1250,9375,15625. This is how to do it. Step 1: The first step is to use the division lemma with 9375 and 1250 because 9375 is greater than 1250. 9375 = 1250 x 7 + 625. Step 2: Here, the reminder 1250 is not 0, we must use division lemma to 625 and 1250, to get. 1250 = 625 x 2 + 0.
WebNotice that 625 = HCF (1250,625) = HCF (9375,1250) . We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma Step 1: Since 15625 > 625, we apply the division lemma to 15625 and 625, to get 15625 = 625 x 25 + 0 The remainder has now become zero, so our procedure stops.
WebThus, the required number should be the H.C.F of 625, 3125, and 15625. First, consider 625 and 3125 and apply Euclid’s division lemma. 3125 = 625 x 5 + 0. ∴ H.C.F (625, 3125) = 625. Next, consider 625 and the third number 15625 to apply Euclid’s division lemma 15625 = 625 x 25 + 0. We get, the HCF of 625 and 12625 to be 625. dun dun sound effect law and orderWebJan 25, 2024 · Best answer. The required number when divides 626, 3127 and 15628, leaves remainder 1, 2 and 3. This means. 626 – 1 = 625, 3127 – 2 = 3125 and. 15628 – … dundurn acreages for saleWebFind the prime factorization of 625. 625 = 5 × 5 × 5 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 5 × 5. GCF = 25. MathStep … dundurn books submissionsWebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Write the given series in summation notation. (125/9) + (625/16) + (3125/25) + (15625/36) +...Infinity of the summation of n=1=?Please show all steps for my understanding. Thank you! dundurn army baseWebJan 16, 2024 · Find the HCF of 625,3125,15625 Advertisement Answer No one rated this answer yet — why not be the first? 😎 aarav873 the HCF is 15625 I hope this helps you if the answer is correct please mark me as a brainliest Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 dundurn chinese foodWeb626 – 1 = 625, 3127 – 2 = 3125 and 15628 – 3 = 15625 has to be exactly divisible by the number. Thus, the required number should be the HCF of 625, 3125 and 15625. First, consider 625 and 3125 and apply Euclid’s division lemma. 3125 = … dundurn booksWebNotice that 625 = HCF (3125,625) . We can take hcf of as 1st numbers and next number as another number to apply in Euclidean lemma. Step 1: Since 15625 > 625, we apply the … dundurn cemetery